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bill huggin
126 PointsI am stumped here...apparently I am printing Learning Swift Swift instead of "Learning Swift"
I am stumped here...apparently I am printing "Learning Swift Swift" instead of "Learning Swift"
What is correct
let language = "Swift"
println("Learning Swift \(language)")
3 Answers
John Magee
Courses Plus Student 9,058 PointsWell - you tell the program to print "Learning Swift" and then you include the variable language that you defined earlier. So you are basically saying "Out put Learning Swift and then follow it with the content of the variable language I set earlier (as Swift)
Jacob McCaig
7,201 Points(language) = "Swift"
You're doing it twice.
John Rainier Rivera
6,355 Pointslet language = "Swift" println("Learning (language)")
Jacob McCaig
7,201 PointsA println() simply outputs to the console whatever you put in it. You are essentially wanting to print "Learning " + whateverIsInTheLanguageVariable.
To do this you use string interpolation. The syntax is "your string here \(yourVariableHere)" and to get that to output to the console, you would place it in a println() function.