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iOS Swift Basics (retired) Types Printing Results

I am stumped here...apparently I am printing Learning Swift Swift instead of "Learning Swift"

I am stumped here...apparently I am printing "Learning Swift Swift" instead of "Learning Swift"

What is correct

let language = "Swift"
println("Learning Swift \(language)")

3 Answers

Well - you tell the program to print "Learning Swift" and then you include the variable language that you defined earlier. So you are basically saying "Out put Learning Swift and then follow it with the content of the variable language I set earlier (as Swift)

(language) = "Swift"

You're doing it twice.

John Rainier Rivera
John Rainier Rivera
6,355 Points

let language = "Swift" println("Learning (language)")

A println() simply outputs to the console whatever you put in it. You are essentially wanting to print "Learning " + whateverIsInTheLanguageVariable.

To do this you use string interpolation. The syntax is "your string here \(yourVariableHere)" and to get that to output to the console, you would place it in a println() function.