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charlesmonaghan
742 PointsI believe I did this right, but I'm not sure why it's not working?
I'm pretty sure I got everything right. But it just returns the error "Bummer! Try again!".
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count("this is a string"):
return {'this': 1, 'is': 1, 'a': 1, 'string': 1}
2 Answers
Logan R
22,989 PointsI think you're reading the comments wrong. It's saying it will run your code with those parameters.
# The function you write
def word_count(words_as_string):
# Make a new dictionary for words and their count.
word_dict = {}
# Sum words
# ...
return word_dict
# --------------------------
# You "can't see" this code, but this is how they will call your function
word_counts = word_count("I do not like it Sam I Am")
# Expected dictionary back:
# >>> print (word_counts)
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
Hopefully, this helps clear up question!
Christian Lamoureux
Full Stack JavaScript Techdegree Student 22,669 PointsI also am struggling with this one here's what I have so far def word_count(value): the_dictionary = {} value = value.lower() my_list = [''.split(value)] word_list = [] for word in my_list: word_list.append(word) if word == word in word_list: word = str(word) number = [] number.append(word) length = len(number) the_dictionary.update({word: length})
else:
the_dictionary.update({word: 1})
continue
return the_dictionary