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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Random Number Challenge, Part II Solution

Fadi Birouti
PLUS
Fadi Birouti
Courses Plus Student 6,711 Points
Posted by Fadi Birouti
Fadi Birouti
Courses Plus Student 6,711 Points

i called throw new Error from other function did't work? any useful idea's

throw new Error didn't' work in console:

/*create randomnumber*/
function getRandomNumber( lower, upper ) { 
 // call function to check if argumetns are numbers// if(checklowerUpper( lower, upper )){}
  else{
  return Math.floor(Math.random() * (upper - lower + 1)) + lower; 
}}

function checklowerUpper( lower, upper ) {
  if (isNaN(lower)|| isNaN(upper)) {throw new Error('error message')}}

console.log( getRandomNumber( 'nine', 24 ) );
console.log( getRandomNumber( 1, 100 ) );
console.log( getRandomNumber( 200, 'five hundred' ) );
console.log( getRandomNumber( 1000, 20000 ) );
console.log( getRandomNumber( 50, 100 ) );

1 Answer

Steven Parker
Steven Parker
229,783 Points
Steven Parker
Steven Parker
229,783 Points

It worked for me.

When I tried your code, It caused the error just as expected. I'm not sure why you would have seen different results.

But there are some issues when the error is not thrown. You call checklowerUpper inside an if expression, but the function checklowerUpper doesn't return any value for the if to test.

Also, when posting code, please use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area. :arrow_heading_down: