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Start your free trialFadi Birouti
Courses Plus Student 6,711 Pointsi called throw new Error from other function did't work? any useful idea's
throw new Error didn't' work in console:
/*create randomnumber*/
function getRandomNumber( lower, upper ) {
// call function to check if argumetns are numbers// if(checklowerUpper( lower, upper )){}
else{
return Math.floor(Math.random() * (upper - lower + 1)) + lower;
}}
function checklowerUpper( lower, upper ) {
if (isNaN(lower)|| isNaN(upper)) {throw new Error('error message')}}
console.log( getRandomNumber( 'nine', 24 ) );
console.log( getRandomNumber( 1, 100 ) );
console.log( getRandomNumber( 200, 'five hundred' ) );
console.log( getRandomNumber( 1000, 20000 ) );
console.log( getRandomNumber( 50, 100 ) );
1 Answer
Steven Parker
231,269 PointsIt worked for me.
When I tried your code, It caused the error just as expected. I'm not sure why you would have seen different results.
But there are some issues when the error is not thrown. You call checklowerUpper inside an if expression, but the function checklowerUpper doesn't return any value for the if to test.
Also, when posting code, please use the instructions for code formatting in the Markdown Cheatsheet pop-up below the "Add an Answer" area.