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JavaScript AJAX Basics (retiring) jQuery and AJAX The Office Status Project Revisited

Carlo Sabogal
Carlo Sabogal
7,468 Points
Posted by Carlo Sabogal
Carlo Sabogal
7,468 Points

I cannot load the employee status, please review my code

I cannot load the employee status, please review my code

$(document).ready(function() {
 var url= "../data/employees.json";
  $.getJSON(url, function (response){
      var statusHTML = '<ul class "bulleted">';
      $.each(response, function(index, employee) {
      if (employee.inoffice === true) {
         statusHTML+='<li class="in">';
      } else {
         statusHTML+='<li class="out">';
      }
    statusHTML+=employee.name +'</li>';
  });
  statusHTML+='</ul>';
  $('#employeeList').html(statusHTML);
  }); //end getJSON  
});// end ready
...

2 Answers

Marcus Parsons
Marcus Parsons
15,719 Points

Hey Carlo,

It looks like you are missing the ending </ul> tag right after your each function:

$(document).ready(function() {
 var url= "../data/employees.json";
  $.getJSON(url, function (response){
      var statusHTML = '<ul class "bulleted">';
      $.each(response, function(index, employee) {
      if (employee.inoffice === true) {
         statusHTML+='<li class="in">';
      } else {
         statusHTML+='<li class="out">';
      }
    statusHTML+=employee.name +'</li>';
  });
  //Added ending ul tag for the unordered list
  statusHTML+='</ul>';
  $('#employeeList').html(statusHTML);
  }); //end getJSON  
});// end ready
Lido Fernandez
Lido Fernandez
10,556 Points
Lido Fernandez
Lido Fernandez
10,556 Points

Hey Carlo,

You also missed an "=" in this part: ul class = "bulleted"