I cannot understand fully

Question

Why then dont working option like this:
```javascript
var buttons = document.getElementsByTagName('button');
function createHandler(name) {  
    return console.log(name);      //without closure function
    }
for(var i = 0; i < buttons.length; i += 1) {
    var button = buttons[i];
    var buttonName = button.innerHTML;
    button.addEventListener('click', createHandler(buttonName));
}
```

Aakash Srivastava · Accepted Answer

Hey @Vladimir Plokhotniuk (https://teamtreehouse.com/vladimirplokhotniuk)  ,   
 Functions are what are called "first class" citizens. You can pass functions to other functions, return functions from functions and even use functions to build other functions .
So , he is creating a function with console.log statement and then returning that function.  
Let's come to the second part , i,e why you can't return a console.log directly :    
console.log(name) is a statement which gets executed not a value which can be returned.
console.log will display the parameter passed to the log method in the console window. Use this method to display a string or variable in the console window.   
When using the return statement, the function will stop executing, and return the specified value.   
You can't combine both the statements.    
Hope this helped.

odzer · Answer

What you posted, without the closure, has no practical difference from the code in the beginning of the video, which was leading to all buttons having the same name. The only difference is that it is declared separately as a named function.
You need the  closure so that every time the button name is passed into the outer function, the inner function keeps the name that it is passed during that call of the outer function. Without the closure, the function simply gets the name from the global scope, so it is always the same.

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Vladimir Plokhotniuk

Vladimir Plokhotniuk

I cannot understand fully

2 Answers

Aakash Srivastava

Aakash Srivastava

odzer

odzer