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# I can't figure out the answer.

function max(number1,number2){

if(parseInt(number1)>>ParseInt(number2)){ return number1; } if else(parseInt(number1)<<parseInt(number2)){ return number2; } }

max(1,2);

script.js
```function max(number1,number2){

if(parseInt(number1)>>ParseInt(number2)){
return number1;
}
if else(parseInt(number1)<<parseInt(number2)){
return number2;
}
}

max(1,2);
```

a parse error don't need to use parseInt. you can delete them. I give you the solution try.

```function max(number1,number2){

if(number1 > number2){
return number1;
}
else {
return number2;
}
}
```

Hi Gaku

```if(parseInt(number1)>>ParseInt(number2)){
```

Since JavaScript is case-sensitive `ParseInt` must begin with a lowercase `P`, but this was probably just a typo. Comparisons for greater than and less than are done with either `>` or `<`. What you are using, `<<` and `>>` are actually bitwise operators (which I don't think are covered here).

```if(condition){
// code
}
if else(condition){
// code
}
```

The proper way to structure an if else statement is:

```if(condition){
// code
} else {
// code
}
```

Since the question never actually asks you to convert any inputs to integers, you can simply leave it off.

```function max(number1, number2){
if(number1 > number1){
return number1;
} else {
return number2;
}
}
```

thank you very much,I finally got it!!