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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Create a max() Function

Posted by Gaku Nagasaku
Gaku Nagasaku
2,427 Points

I can't figure out the answer.

function max(number1,number2){

if(parseInt(number1)>>ParseInt(number2)){ return number1; } if else(parseInt(number1)<<parseInt(number2)){ return number2; } }

max(1,2);

script.js 
function max(number1,number2){

if(parseInt(number1)>>ParseInt(number2)){
   return number1;
}
if else(parseInt(number1)<<parseInt(number2)){
   return number2;
}
}

max(1,2);
Sandro Das Neves
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Sandro Das Neves
Front End Web Development Techdegree Graduate 23,426 Points
Sandro Das Neves
.a{fill-rule:evenodd;}techdegree seal-36
Sandro Das Neves
Front End Web Development Techdegree Graduate 23,426 Points

a parse error don't need to use parseInt. you can delete them. I give you the solution try.

function max(number1,number2){

if(number1 > number2){
   return number1;
}
  else {
   return number2;
  }
}

1 Answer

Umesh Ravji
Umesh Ravji
42,386 Points
Umesh Ravji
Umesh Ravji
42,386 Points

Hi Gaku

if(parseInt(number1)>>ParseInt(number2)){

Since JavaScript is case-sensitive ParseInt must begin with a lowercase P, but this was probably just a typo. Comparisons for greater than and less than are done with either > or <. What you are using, << and >> are actually bitwise operators (which I don't think are covered here).

if(condition){
   // code
}
if else(condition){
   // code
}

The proper way to structure an if else statement is:

if(condition){
   // code
} else {
   // code
}

Since the question never actually asks you to convert any inputs to integers, you can simply leave it off.

function max(number1, number2){
  if(number1 > number1){
     return number1;
  } else {
     return number2;
  }
}
Gaku Nagasaku
Gaku Nagasaku
2,427 Points

thank you very much,I finally got it!!