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Ruby Ruby Basics (Retired) Ruby Methods Method Returns: Part 2

Posted by Ben Santen
Ben Santen
1,998 Points

i can't figure out the problem with my code.

It sais i have incorrect puncuation but i don't think i do

method.rb 
def mod(a,b)
  return "The remainder of #{a} divided by #{b} is c:"
  puts a % b
end

mod(5,2)

1 Answer

Steve Hunter
Steve Hunter
57,712 Points
Steve Hunter
Steve Hunter
57,712 Points

Hi Ben,

You're pretty much there with that.

The issue is that c doesn't exist. So, either create c at the top of the method, assign the value of a % b to it then include it in the output string with #{c} or just enclose a % b inside the braces. Also, delete the puts line - we're returning values here, not printing them to the screen.

Make sense?

Steve.