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Python Django REST Framework RESTful Django Create a ListView

Posted by Tinotenda Tariro Mhishi
Tinotenda Tariro Mhishi
9,877 Points

I cant figure out what i am doing wrong @kennethlove

I followed every step but i keep gettinh a bummer

scorekeeper/views.py 
from rest_framework.views import APIView
from rest_framework.response import Response

from . import models
from . import serializers

class GameList(APIView):
    def get(self, request, format=None):
        games = models.Game.objects.all()
        serializer = serializers.GameSerializer(games, many=True)
        return Response(serializer.data)
scorekeeper/urls.py 
from django.conf.urls import url
from . import views


urlpatterns = [
    url(r'^games /$', views.GamesList.as_view(), namespace='game_list'),


]

1 Answer

Chris Howell
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Chris Howell
Python Web Development Techdegree Graduate 49,702 Points
Chris Howell
.a{fill-rule:evenodd;}techdegree seal-36
Chris Howell
Python Web Development Techdegree Graduate 49,702 Points

Hi Tinotenda Tariro Mhishi

So it looks like you have a few errors within urls.py.

HINT: You have 3 errors, all on this line.

url(r'^games /$', views.GamesList.as_view(), namespace='game_list'),

I will help you with one.

namespace is only used when you are using include(). There is a similar one that you use for the given apps urls.py file

# Example of using namespace, namespace isnt the one you want to use.
url(r'^some-app/', include('some_app.urls', namespace='some_name'))

Your other two are 1 character fixes. :)

Tinotenda Tariro Mhishi
Tinotenda Tariro Mhishi
9,877 Points

thanks. will try revisiting the line