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Python Python Collections (2016, retired 2019) Lists Disemvowel

Posted by Tan Yang
Tan Yang
13,163 Points

I can't pass this challenge. I don't know what is the problem of it.

help

disemvowel.py 
def disemvowel(word):
    new_list = word.split(", ")

    for letter in new_list.copy():
        if letter.lower()=='a':
            new_list.remove(letter)
        elif letter.lower()=='e':
            new_list.remove(letter)
        elif letter.lower()=='i':
            new_list.remove(letter)
        elif letter.lower()=='o':
            new_list.remove(letter)
        elif letter.lower()=='u':
            new_list.remove(letter)
        else:
            pass

    return ", ".join(new_list)

1 Answer

mayan porat
PLUS
mayan porat
Courses Plus Student 2,144 Points
mayan porat
mayan porat
Courses Plus Student 2,144 Points

I think the use in split method is the problem. The method returns a list of strings after breaking the given string by the specified separator, if a separator given, the string splits at a specified separator. For example if your word value is: "I,learn,python" and you use word.split(",") then the list would be: ['I', 'learn', 'python'], but if your word value is: "WindOw" then word.split(",") outcome would be ['WindOw'] because there are no "," separators in the string. Since in this challenge the origin word letters are not separated by "," in your code 'new_list' is actually a single value list that contains the entire word the function got.

I think you should use list(word) here, the list(x) method creates a list of x string's elements.