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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Alexander Bilton
Alexander Bilton
1,982 Points

I can't see why this function is not accepted?


I tried to run this code in workspaces, and it seems to me that it returns what is required. Can someone tell me why this is not accepted in the challenge?

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(str1):
    word_lst = str1.lower().split(' ')
    word_dict = {}

    for item in word_lst:
        if not item in word_dict:
    return word_dict

1 Answer