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Python Practice Creating and Using Functions in Python Practice Functions Use an External Function

Posted by Luke Tate
Luke Tate
Courses Plus Student 2,256 Points

I can't seem to figure out how to output the try again error message on the except CommunicationErrror.

using_a_function.py 
"""
This is importing a function named `tweet` from a file
    that we unfortunately don't have access to change.

You use it like so:
>>> tweet("Hello this is my tweet")

If the function cannot connect to Twitter,
    the function will raise a `CommunicationError`
If the message is too long,
    the function will raise a `MessageTooLongError`
"""
from twitter import (
    tweet,
    MessageTooLongError,
    CommunicationError,
)
try:
    message = input("What would you like to tweet?  ")
# Your code here
except CommunicationError:
        print("An error has occurred trying to connect to Twitter!/n Please try again!")


try:
    tweet(message)
except CommunicationError:
        print("You have a problem connecting to Twitter.")

except MessageTooLongError as err:
        print("The message is too long. {err}")

1 Answer

boi
boi
14,241 Points
boi
boi
14,241 Points

Why are you using two try blocks? one try block can catch more than one Exception, try using one try block with both the Exceptions., also a few points to consider here;

1) Your line of code,

                                print("The message is too long. {err}")

is incorrect.

2) The challenge requires you to print the exact messages described, it seems like your second try block's first Exception messaging is a little off, you are missing the "Please try again" part.

Make these changes, if the problem persists, post back here

Luke Tate
Luke Tate
Courses Plus Student 2,256 Points

Thank You!