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PHP Build a Basic PHP Website (2018) Adding a Basic Form Objects

Posted by Prince Gurajena
Prince Gurajena
11,438 Points

i can't write the conditional using the right syntax

i can't write the conditional using the right syntax

palprimes.php 
<?php

include("class.palprimechecker.php");
$checker = new PalprimeChecker;
$checker -> number = 17;




$bool = true;

echo "The number  ".$checker->number;
echo "((isPalprime($checker->number)== $bool )?is|is not)";
echo " a palprime.";

?>
Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

isPalprime is a method on the checker, so it has to be called on $checker. You don't need to test against true, a conditional does that already.

1 Answer

Simon Coates
Simon Coates
28,694 Points
Simon Coates
Simon Coates
28,694 Points

Following seems to work

<?php

include("class.palprimechecker.php");
$checker = new PalprimeChecker;
$checker -> number = 17;

echo "The number  ".$checker->number;
echo ($checker->isPalprime())? " is ": " is not ";
echo " a palprime.";

I assume you're comfortable with the ternary operator.