Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Letter Game App Random Item

Posted by Victor Katsande
Victor Katsande
3,094 Points

i corrected some errors but still wont pass.

Here is the body of the question

I want you to try and reproduce it yourself.

First, import the random library.

Then create a function named random_item that takes a single argument, an iterable. Then use random.randint() to get a random number between 0 and the length of the iterable, minus one. Return the iterable member that's at your random number's index.

Check the file for an example.

item.py 
import random
def random_item(iterable)
     random_number = random.randint(0, len(list(iterable))-1)
     return iterable[random_number]

1 Answer

matth89
matth89
17,826 Points

Very close. You're missing a colon on your function, and you don't need to convert your iterable to a list. Here's a working example 

import random

def random_item(arg):
    rand_num = random.randint(0, len(arg) -1)
    return arg[rand_num]