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iOS Swift 2.0 Functions Function Parameters Function Parameters

Ryan Maneo
Ryan Maneo
4,342 Points

I did what it asked...

Task: "In this task we're going to write a simple function that takes two numbers and returns the remainder of dividing one number by the other.

Step 1: Declare a function named getRemainder that takes two parameters, aand b, both of type Int, and returns the value, also of type Int, obtained by carrying out the operation a modulo b. In case you've forgotten, the modulo operator is also called the remainder operator.

Step 2: The local names of the parameters are convenient but they make it hard to figure out the meaning of the function when we call it. Add two external names - value, for the first parameter and divisor for the second."

my response below...

functions.swift
// Enter your code below

func getRemainder(a value: Int, b divisor: Int) -> Int {
    return a % b
}

2 Answers

Steven Deutsch
Steven Deutsch
21,046 Points

Hey Ryan Minnick,

You have the external and local parameter names mixed up. The external name comes before the local name, and is used for the argument names of the function call. The local name foes after the external name and before your type declaration. You use the local name inside of the function body.

// Enter your code below

func getRemainder(value a: Int, divisor b: Int) -> Int {
    return a % b
}

Good Luck!

Ryan Maneo
Ryan Maneo
4,342 Points

Thank you! I guess he should have clarified that a was the local parameter. Not value.

This one confused me also. I think that the earlier example for sayHello confused is for me since it was not at all clear what where the local names and what were the external names.