Abdullah Jassim4,551 Points
I didnt understand this video from 3:50 onwards. The following are my specific questions:
1) How does the .pop() function change the list?
- my understanding of the .pop() function is that it merely returns either the last item or the indexed item. So how does this change the list?
2) I did not understand the explanation of how it changes in 4:36 - 4:48.
- My understanding is that in def DISPLAY_WISHLIST, both DISPLAY_NAME and WISHES are parameters and they are objects. The labels applied to these parameters are Books and books. Correct? After this I still dont understand how .pop changes the list item.
3) How does making a copy of the list not change the list?
Thanks in advance.
Derek Lefler2,608 Points
def display_wishlist(display_name, wishes): print(display_name + ":") suggested_gift = wishes.pop(0) print("======>", suggested_gift, "<=======") for item in items: print("* " + item) print()
.pop() returns an item from the list and then drops off that item from the list (the last item if not specified). So in the lesson's example,
suggested_gift = wishes.pop(0) print("======>", suggested_gift, "<=======")
pop(0) returned wishes and then removed the first item from the list.
for wish in wishes: print("* " + wishes)
So when this part of the function is executed, wishes doesn't include the book "Learning Python..." or the video game "Legend of Zelda...." because pop(0) removed it before.
Alex KoumparosPython Web Development Techdegree Student 35,870 Points
1) Your understanding of
pop() is not quite correct. Let's look at the documentation:
list.pop(i) Remove the item at the given position in the list, and return it.
It is the removing the item from the given position part that modifies the list.
wishes are parameters, and they are objects (everything in Python is an object).
books are the arguments provided for those parameters. The reason that
pop() changes the list item is entirely down to the behaviour of the
pop method itself, which always changes the list on which the method is called.
my_list = ["hello", "there", "abdullah"] word = my_list.pop(0) print(word) # hello print(my_list) # ['there', 'abdullah']
As you can see in this simple example,
pop() always does two things: 1: it takes the specified item (or last item if None specified) out of the list and 2: it returns that item.
3) Making a copy of the list is creating an entirely new list and filling it with the items that are in the old list. Consider this simple example:
my_list = ["hello", "there", "abdullah"] word = my_list print(word) # hello print(my_list) # ['hello', 'there', 'abdullah']
Hopefully it's clear that just reading a value from a list and putting that value in a variable doesn't modify the original list. We can extend the example slightly:
my_list = ["hello", "there", "abdullah"] words = my_list[0:2] print(words) # ['hello', 'there'] print(my_list) # ['hello', 'there', 'abdullah']
Here we've done basically the same thing, but instead of reading one value out of the list, we've read the items from index 0 ('hello') to the last item before index 2 ('there'). Again, we're just reading the values out of the original list, so the original list remains unchanged.
Lastly, we can extend the example to copying the whole list:
my_list = ["hello", "there", "abdullah"] words = my_list[:] print(words) # ['hello', 'there', 'abdullah'] print(my_list) # ['hello', 'there', 'abdullah']
As you can see, this is exactly the same, except we are telling Python to read all the values from the beginning of the original list to the end of it.
Hope that clears everything up for you