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Sajid Latif
Full Stack JavaScript Techdegree Student 22,368 PointsI do not get the question. Who can help?
What does this question means?
Add a getInfo method to your Trout class that returns a string containing the common_name, flavor, record_weight, and species properties. For example, on our brook trout it might return "Brook Trout tastes Delicious. The record Brook Trout weighed 14 pounds 8 ounces."
<?php
class Fish
{
public $common_name;
public $flavor;
public $record_weight;
function __construct($name, $flavor, $record){
$this->common_name = $name;
$this->flavor = $flavor;
$this->record_weight = $record;
}
public function getInfo() {
$output = "The {$this->common_name} is an awesome fish. ";
$output .= "It is very {$this->flavor} when eaten. ";
$output .= "Currently the world record {$this->common_name} weighed {$this->record_weight}.";
return $output;
}
}
class Trout extends Fish {
public $species;
function __construct($name, $flavor, $record, $species){
parent::__construct($name, $flavor, $record);
$this->species = $species;
}
public function getInfo() {
$output = $this->species. " " . $this->name . "tastes " . $this->flavor .".";
$output .= "The record ". $this->species . " " . $this->name;
$output .= "weighed " . $this->record .".";
return $output;
}
}
$brook_trout = new Trout("Trout", "Delicious", "14 pounds 8 ounces", "Brook");
echo $brook_trout->getInfo();
?>

Sajid Latif
Full Stack JavaScript Techdegree Student 22,368 PointsAdd a getInfo method to your Trout class that returns a string containing the common_name, flavor, record_weight, and species properties. For example, on our brook trout it might return "Brook Trout tastes Delicious. The record Brook Trout weighed 14 pounds 8 ounces."
2 Answers

Grace Kelly
33,990 PointsHi Sajid, I think the issue is you have used "name" and "record" in your getInfo() method when you should be using "common_name" and "record_weight", try changing your code to the following:
<?php
public function getInfo() {
$output = $this->species. " " . $this->common_name . "tastes " . $this->flavor ."."; //changed name to common_name
$output .= "The record ". $this->species . " " . $this->common_name; //changed name to common_name
$output .= "weighed " . $this->record_weight ."."; //changed record to record_weight
return $output;
}
?>
Hope that helps!!

Sajid Latif
Full Stack JavaScript Techdegree Student 22,368 PointsOfcourse. See it now. I should have known that :)
Tony Nguyen
24,934 PointsTony Nguyen
24,934 PointsWhat is the question asking?