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Anurag Gracian315 Points
i do not know why my string variable is not working
i defined the string variable. but the code is not working
// I have setup a java.io.Console object for you named console String firstName = "Anurag"; console.printf("%s\n, firstName"); } }
Hey there Anurag!
Your code is almost perfect.
The console.printf() function requires one extra argument for every formatter you pass into it. Take this as an example:
console.printf("%s %s %s %s"); //This will throw an error.
You have 4 string formatters, which means you must have 4 strings (either as literals or variables) passed into the method.
The code, when properly written, would look like this:
String one = "one"; String two = "two"; String three = "three"; String four = "four"; console.printf("%s %s %s %s", one, two, three, four); //The console will display: one two three four
For your code specifically, you need to remove "firstName" from the string and rewrite it like so:
// I have setup a java.io.Console object for you named console String firstName = "Anurag"; console.printf("%s\n", firstName); } }
This is telling the printf() function that you have a string ("%s\n") with one variable/literal being passed into it (firstName).
Hopefully this helps. :-)