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PHP

Neslee Rodillo
Neslee Rodillo
19,615 Points
Posted by Neslee Rodillo
Neslee Rodillo
19,615 Points

i do not understand objects in php

Can someone explain this to me in laymans terms??

Challenge task 5 of 7 PalprimeChecker objects have a method called isPalprime(). This method does not receive any arguments. It returns true if the number property contains a palprime, and it returns false if the number property does not contain a palprime. (Tip: 17 is not a palprime.) Turn the second echo statement into a conditional that displays “is” or “is not” appropriately. The conditional should call the isPalprime method of the $checker object. If the isPalprime method returns true, then echo “is”; otherwise, echo “is not”.

My answer:

<?php

include "class.palprimechecker.php";

$checker = new PalprimeChecker();
$checker->number = 17;
echo "The number 17 ";

if (isPalprime($checker) !== FALSE) {

  echo " is not";
}

echo " a palprime.";

?>

Ouctcome: Bummer, Try again

4 Answers

Chris Wiley
Chris Wiley
11,327 Points
Chris Wiley
Chris Wiley
11,327 Points

Try this for a false check:

  include("class.palprimechecker.php");

$checker = new PalprimeChecker;
$checker->number = 17;


echo "The number 17 ";
if (!$checker->isPalprime()) {
echo "is not";
}else{
  echo "is";
}
echo " a palprime.";

?>``` 

Just put he ' ! ' in front if the object and invert the execution order.
Iaan Tatenda Ruwiza
Iaan Tatenda Ruwiza
12,712 Points
Iaan Tatenda Ruwiza
Iaan Tatenda Ruwiza
12,712 Points

include("class.palprimechecker.php"); $checker = new PalprimeChecker(); $checker->number = 17;

if($checker -> isPalprime()){ echo "The number " . $checker->number . " is a palprime."; } else { echo "The number " . $checker->number . " is not a palprime."; }

Jason Cullins
PLUS
Jason Cullins
Courses Plus Student 4,893 Points
Jason Cullins
Jason Cullins
Courses Plus Student 4,893 Points

To me, it looks like you have this backwards... but this:

if (isPalprime($checker) !== FALSE) {

should probably be:

if ($checker->isPalprime !== FALSE {

because you set:

$checker = new PalprimeChecker();

so now the methods are inside of your $checker object.

Hope this helps you.

John MacDonald
John MacDonald
8,593 Points
John MacDonald
John MacDonald
8,593 Points

Hey Neslee

Instead of php if(isPalprime($checker) !== FALSE) change it to php if(isPalprime($checker->name) !== FALSE)

I think that should work.

Hope this helps

John; \n\n