Josh O.941 Points
I do not understand what I am doing wrong. I have added 5 to integerOne even printed the result (echo).
I Added 5 to $integerOne and subtracted 1 from $integerTwo. I even displayed the correct answer by using echo. Then I started over and just added and subtracted the appropriate numbers. still it returned an warning "Bummer: you haven't changed $integerOne.
Here was my original code: $integerOne =1; $integerTwo = 2; $floatOne = 1.5; $answerOne = $integerOne + 5; $answerTwo = $integerTwo -1; echo $answerOne; echo " and " echo $answerTwo;
<?php //Place your code below this comment $integerOne = 1; $integerTwo = 2; $floatOne = 1.5; $integerOne + 5; $integerTwo - 1; ?>
Since you are adding a value to a variable that has been initialized, you will need to specify the variable name when you add or subtract a number. It looks kind of confusing when you're first starting off. You can do something like this:
variable1 = variable1 + 5;
Or this is also correct:
variable1 += 5;