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Python

Posted by Mateo Rial
Mateo Rial
3,694 Points

I don´t understand why it doesnt run the same way in the video ...if I guess all the letters the program continue asking

import random
words=[
     "apple",
     "banana",
     "orange",
     "coconut",
     "strawberry",
     "lime",
     "grapefruit",
     "lemon",
     "kumquat",
     "blueberry",
     "melon"
]
while True:
    start=input("Press enter to start or Q to quit")
    if start.lower()=="q":
        break
    secw=random.choice(words)
    badg=[]
    goodg=[]

    while len(badg) < 7 and len(goodg)!=len(list(secw)):
        for let in secw:
            if let in goodg:
                print(let,end="")
            else:
                print("_",end="")
        print("")
        print("strikes: {}/7".format(len(badg)))
        print("")
        guess=input("Guess a letter: ").lower()
        if len(guess) != 1:
            print("You can only guess a single letter!")
            continue
        elif guess in badg or guess in goodg:
            print("You´ve already guess that letter!")
            continue
        elif not guess.isalpha():
            print("You can only guess letters!: ")
            continue

        if guess in secw:
            goodg.append(guess)
            if len(goodg) == len(list(secw)):
                print("You win! The word was {}".format(secw))
                break
        else:
            badg.append(guess)
    else:
        print("You didnt guess it! the secret word was {}".format(secw))

1 Answer

Sean Manners
Sean Manners
14,816 Points
Sean Manners
Sean Manners
14,816 Points

I would run the program a few times, at least until you get a word that doesn't have a duplicate letter in it (like 'lemon'). One thing I noticed on this challenge is it may keep running if it has duplicate letters, as it considers you complete if the number of guesses is equal to the secret word. The problem with that is that if there are two or more of the same letter, that condition can never be true because multiple 'e' s' will not count as you guessing three of them, but rather one guess that fills three spots.