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# i dont how to solve this

Tell me how to solve this problem

ScrabblePlayer.java
```public class ScrabblePlayer {
// A String representing all of the tiles that this player has
private String tiles;

public ScrabblePlayer() {
tiles = "";
}

public String getTiles() {
return tiles;
}

tiles += tile;
}

public boolean hasTile(char tile) {
return tiles.indexOf(tile) != -1;
}

public int getCountOfLetter(char letter) {
int counter = 0;
for(char let : tiles.toCharArray()) {
if(tiles.charAt(counter) == letter) {
counter++;
}
}
return counter;
}

}
```
Example.java
```// This code is here for example purposes only
public class Example {

public static void main(String[] args) {
ScrabblePlayer player1 = new ScrabblePlayer();

ScrabblePlayer player2 = new ScrabblePlayer();

int count = 0;
// This would set count to 1 because player1 has 1 'p' tile in her collection of tiles
count = player1.getCountOfLetter('p');
// This would set count to 2 because player1 has 2 'd'' tiles in her collection of tiles
count = player1.getCountOfLetter('d');
// This would set 0, because there isn't an 'a' tile in player1's tiles
count = player1.getCountOfLetter('a');

// This will return 3 because player2 has 3 'z' tiles in his collection of tiles
count = player2.getCountOfLetter('z');
// This will return 1 because player2 has 1 'f' tiles in his collection of tiles
count = player2.getCountOfLetter('f');
}
}
```

``` public int getCountOfLetter(char letter) {
int counter = 0;
for ( int x: tiles.toCharArray() ) {
if( x == letter) {
counter++;
}
}
return counter;
}
```

Here it is how i did , so the x is a variable that stores the char from tiles . You did it almost good just instead of tiles.charAt(counter) put let .