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Java Java Basics Using your New Tools Fix the Errors

Hassan Osman
Hassan Osman
628 Points
Posted by Hassan Osman
Hassan Osman
628 Points

i dont know

heeeeeelp challnege 4/4

FixMe.java 
 String firstName = "Gordon";

 String lastName = "Sumner";

 console.printf("%sHello %s", firstName,lastName);
String = console.readLine("gordon summer: ") ;

3 Answers

Kristian Terziev
Kristian Terziev
28,449 Points
Kristian Terziev
Kristian Terziev
28,449 Points

You replaced the variable name with it's type. They should both appear in your code. That means:

String band = console.readLine("Which band?  ");
Jeremiah Montano
Jeremiah Montano
7,221 Points
Jeremiah Montano
Jeremiah Montano
7,221 Points

When utilizing a readLine, or any variable initialization for that matter, you need to have a variable declared after the type. String is the type of variable, but you need to store the input somewhere. The following code you have String = console.ReadLine("Message"); will break because there is nothing to store the input in to. Using String someVariable = console.readLine("Input something: "); would work because now you have a place to store your input.

I hope this helps! Happy coding!

Oscar Pino
Oscar Pino
2,005 Points
Oscar Pino
Oscar Pino
2,005 Points

in the fourth sentence, you must enter the variable name because you just have the data type.