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Start your free trialVic A
5,452 Pointsi don't know what i'm doing on this one
need help
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(x):
for word in x.split():
if
2 Answers
Steven Parker
231,269 PointsGood start.
And you could lowercase the string as you split it. You might start by declaring the (empty) dictionary that you will build. Then in your loop, you could check if each word is already in the dictionary and increment the count if so, otherwise add it in with a starting count of 1.
Then just return the dictionary when the loop is done.
Vic A
5,452 Pointsi got it thanks
Vic A
5,452 PointsVic A
5,452 Pointshow to I add a value to a dictionary key? What I'm doing isn't working.
Steven Parker
231,269 PointsSteven Parker
231,269 PointsDo you mean increment a value already present? Then something like
mydict[key] += 1
Or if you mean add a new key and value
mydict[key] = 1