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JavaScript JavaScript Basics (Retired) Working With Numbers Create a random number

Karls Yee
Karls Yee
725 Points
Posted by Karls Yee
Karls Yee
725 Points

I don't know why is adding 1 so that we can have a number between 1 and 6

I don't know why is adding 1 to Math.floor so that we can have a number between 1 and 6

4 Answers

Kevin Gates
Kevin Gates
15,052 Points
Kevin Gates
Kevin Gates
15,052 Points

Put another way, random includes the lower limit, but not the upper. So Math.Random is greater than or equal to 0 AND less than 1.

So in the Math.random * 6, your options range from 0 - 5.999999999999999999999999....etc.

Your Math.floor on this limits the options then to 0,1,2,3,4,5. You add plus 1, so the options are now 1,2,3,4,5,6.

ken schafer
ken schafer
13,263 Points
ken schafer
ken schafer
13,263 Points

this was probably the most helpful comment here to explain. Good Job.

Steven Parker
Steven Parker
229,786 Points
Steven Parker
Steven Parker
229,786 Points

The "Math.floor" function is essentially a "round down", so any number less than 1 will become 0. You then add 1 so that the final range will start at 1 instead of 0.

If you don't add the 1, you'll have a random number between 0 and 5.

Nelson J
Nelson J
7,411 Points

what if you get 6, why then is it the 1 not added? because we asked for a number up to 6 and therefore it can't go up anymore, it doesn't make sense or know how to explain.

Steven Parker
Steven Parker
229,786 Points
Steven Parker
Steven Parker
229,786 Points

You can only get 6 because 1 is added. When you multiply random() by 6, and then use the "floor' function, the result will be something from 0 to 5 since random() by itself is always less than 1.

Rafael Castillo
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Rafael Castillo
Front End Web Development Techdegree Student 10,301 Points
Rafael Castillo
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Rafael Castillo
Front End Web Development Techdegree Student 10,301 Points

I was confused by this as well. After going through the code, my notes and watching the video a few times, I finally understood it.

This line: Math.floor(Math.random() * 6); -this will give you a random number from 0 upto but not including 5.

However, the instructor wants a random number like a die/dice throw, which is a number from 1 to 6. Not adding the +1 at the end, again, produces a number from 0 to 5.

Adding the +1 allows us to achieve the objective of a random number from 1 to 6 because a random number of 0 has the 1 added to it to produce the number 1.

Steven Parker
Steven Parker
229,786 Points
Steven Parker
Steven Parker
229,786 Points

I think you meant to say:

This line: Math.floor(Math.random() * 6); -this will give you a random number from 0 upto but not including 6

Seokhyun Wie
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Seokhyun Wie
Full Stack JavaScript Techdegree Graduate 21,606 Points
Seokhyun Wie
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Seokhyun Wie
Full Stack JavaScript Techdegree Graduate 21,606 Points

For instance,

  • Math.ceil(4.5) = 5
  • Math.floor(4.5) = 4

So, 0 <= Math.random() < 1 (check MDN)

  • 0 <= Math.random()*6 < 6
  • 1 <= Math.random()*6 + 1 < 7 In conclusion,

  • 1 <= Math.floor(Math.random()*6) <= 6 (Integer numbers)

  • 0 <= Math.ceil(Math.random()*6) <=6 Because Math.random() can be 0 and *6 still equals zero. So Math.ceil returns zero. Therefore, it cannot be used on making a random dice roller.