Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

iOS Functions in Swift Adding Power to Functions Function Parameters

Nigel Matheson
Nigel Matheson
Courses Plus Student 1,166 Points

I don't know why this is not working

I believe I had got this right but it still doesn't work?


// Enter your code below
func getRemainder (value a: 10, divisor b: 3) -> Int { return a % b}

let result = getRemainder (value: 10, divisor: 3) 

2 Answers

Jeff McDivitt
Jeff McDivitt
23,970 Points

In your function the values are of type Int. You do not input numbers until you call the function

func getRemainder(value a: Int, divisor b: Int) -> Int {

return a % b