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iOS Objective-C Basics (Retired) Fundamentals of C Arrays

I don't know why this isn't working.

Trying to assign letters to char variables e.g.:

char alpha = a; char bravo = b;

This won't pass. Since it's a challenge on arrays I thought this might work:

char alpha[1]; alpha[1] = a char bravo[1]; bravo[1] = b;

Struggling to understand how else to declare these variables under char.

This discussion hasn't created second lines for the code I have written. Assume a new line whenever you see a ;

2 Answers

Stone Preston
Stone Preston
42,016 Points

char variables need single quotes around them:

char alpha = 'a'; 
char bravo = 'b';

Great! Thanks! Man code is fanatical :)