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# I don't really know how to do this one

I have attempted to find all numbers and ignore only 5, 6, and 7 however the code finds all numbers and includes 5,6, and 7

negate.py
```import re

string = '1234567890'

good_numbers = re.findall(r'\d*[^567]', string)
```

"Match any number of digits, followed by one character that is not 5, 6 or 7."

This should do what the challenge is asking, which is match any number of characters except 5, 6 or 7 :

```import re

string = '1234567890'

good_numbers = re.findall(r'[^567]*', string)
```

I figured it out shortly after posting the question but I appreciate the help

I didn't like the way the question was phrased. I thought they should have added the expected result. The expected result is actually ['1', '2', '3', '4', '8', '9', '0']. Yours got ['1234567890']. Can you solve it now?

actually now I go no clue what they wanted :(. Stuart's answer works too and produces ['1234', '', '', '', '890', ''].... my solution was good_numbers = re.findall(r'[^567]', string) and produced ['1', '2', '3', '4', '8', '9', '0'].

Yes good point, it's not very clear what they want. Reading the question again I think yours is the solution they're after, but it's odd that mine gets accepted too.