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dylan hamm3,667 Points
I don't really know how to do this one
I have attempted to find all numbers and ignore only 5, 6, and 7 however the code finds all numbers and includes 5,6, and 7
import re string = '1234567890' good_numbers = re.findall(r'\d*[^567]', string)
Stuart Wright41,101 Points
Your regular expression reads:
"Match any number of digits, followed by one character that is not 5, 6 or 7."
This should do what the challenge is asking, which is match any number of characters except 5, 6 or 7 :
import re string = '1234567890' good_numbers = re.findall(r'[^567]*', string)
Tri Pham18,671 Points
I didn't like the way the question was phrased. I thought they should have added the expected result. The expected result is actually ['1', '2', '3', '4', '8', '9', '0']. Yours got ['1234567890']. Can you solve it now?