Welcome to the Treehouse Community
The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

Phuc Nguyen
367 PointsI don't really understand what should I do in this challenge
I don't really understand what should I do in this challenge
// I have setup a java.io.Console object for you named console
String firstName = "Phuc";
console.printf("%s can code in java!" firstName);
1 Answer

Jason Wiram
42,184 PointsYour answer is almost correct. Your console.printf should pass the value of the firstName variable into the string by replacing the %s placeholder. There is one small syntax error causing you to not pass. You must put a comma between the string and the variable you are passing to it.
String firstName = "Phuc";
console.printf("%s can code in java!", firstName);

Craig Dennis
Treehouse TeacherHi @Phuc Nguyen! Did Jason Wiram 's answer help? If so can you mark it with best answer please?
Phuc Nguyen
367 PointsPhuc Nguyen
367 Pointsthe question was: " Now replace <YOUR NAME> in the console.printf expression with the firstName variable using the string formatter."