
CESAR AGUILAR
Python Development Techdegree Student 710 Pointsi dont remember how to catch the "CommunicationError" in a try except block
"""
This is importing a function named `tweet` from a file
that we unfortunately don't have access to change.
You use it like so:
>>> tweet("Hello this is my tweet")
If the function cannot connect to Twitter,
the function will raise a `CommunicationError`
If the message is too long,
the function will raise a `MessageTooLongError`
"""
from twitter import (
tweet,
MessageTooLongError,
CommunicationError,
)
message = input("What would you like to tweet? ")
tweet(message)
from twitter import(tweet)
try:
print(CommunicationError)
except:
print("An error occurred attempting to connect to Twitter. Please try it again!")
1 Answer

Joseph Yhu
PHP Development Techdegree Graduate 46,146 PointsYou just have to type CommunicationError
in between except
and the colon. Also you should put tweet(message)
inside the try
block, and you don't need from twitter import(tweet)
.
Liam White
1,104 PointsLiam White
1,104 PointsJoseph Yhu - Hey there! I'm having a difficult time with this same challenge. I followed your instructions above but I'm still getting an error. Is there something else that needs to be done? Thank you