Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trial
ali tawbe
642 Pointsi don't see any mistake in coding but the bummer said double check your Fizz logic and make
sure returning the correct string
func fizzBuzz(n: Int) -> String {
// Enter your code between the two comment markers
for i in 1...100 {
if n % 3 == 0 && n % 5 == 0 {
print("FizzBuzz")
} else if n % 3 == 0 {
print("Fizz")
} else if n % 5 == 0 {
print("Buzz")
} else {
print (n)
}
}
// End code
return "\(n)"
}
2 Answers
Ivan Kazakov
Courses Plus Student 43,317 PointsHi Ali.
First, you don't actually need a loop. Second, you've been asked to return "Fizz", "Buzz", "FizzBuzz" or the number itself, not to print.
Jason Anders
Treehouse Moderator 145,855 PointsIvan is correct. The for loop needs to be deleted. The print needs to be return. And, also you need to delete the final else statement.
Challenges are very specific and very picky. You'll need to pay very close attention to the instructions in each challenge. Even a missing period will result in a Bummer! (if the challenge asks for one).
Keep Coding! :)
