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JavaScript JavaScript Foundations Arrays Methods: Part 2

Patrick Ludwig
Patrick Ludwig
2,462 Points
Posted by Patrick Ludwig
Patrick Ludwig
2,462 Points

I don't think this was covered in the video

This challenge asks me to sort the saying2 string "so that the words are listed in length order." However, it keeps giving me an error message saying that the string is now not in the original order. Don't we have to change the order to put them in "length order?" I am very confused.

index.html 
<!DOCTYPE html>
<html lang="en">
  <head>
    <title> JavaScript Foundations: Arrays</title>
    <style>
      html {
        background: #FAFAFA;
        font-family: sans-serif;
      }
    </style>
  </head>
  <body>
    <h1>JavaScript Foundations</h1>
    <h2>Arrays: Methods Part 1</h2>
    <script>
      var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
      var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
      saying1.reverse();
      saying2.sort(function(){
        return saying2.length;
      });
    </script>
  </body>
</html>

2 Answers

Danielle Hill
Danielle Hill
26,062 Points
Danielle Hill
Danielle Hill
26,062 Points

Hi Patrick. The question calls for using a comparative function with the sort method that was covered in the video. It requires writing a function to compare the lengths of two arguments, let's say a and b. 

function (a, b) {  }

This function must return the difference in the length of a and the length of b. 

function (a, b) { return a.length - b.length;}

Passing this function to the sort method will change the order of the array based on length.

saying2.sort(function (a, b) { return a.length - b.length;});