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sami thakur
970 PointsI dont understand this?
im doing what its teling me to, but its not working still?
var players = ['Jim', 'Shawna', 'Andrew', 'Lora', 'Aimee', 'Nick'];
console.log = players[0];
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
nico dev
20,364 PointsAlmost there!
Remember the console.log() is a method, not a variable.
If you do this:
//variables
myVariable = players[0]; // You're telling whatever variable is on the left to take the value on the right
//methods
console.log(whatever you want to print out to console goes here) // You're telling the method to perform its instructions on whatever is inside the parentheses (called argument).
If you still have doubts after trying this, feel free to follow up here. Keep it up!
Karan Nahar
16,157 Points//To print the first element to the console
console.log( players[0] );
//looping through the players array to access every element
for(i=0; i < players.length; i++){
console.log( players[i] );
}
console is an object with a log method on it. You can pass it values that you want to print out to your browser's console.