Welcome to the Treehouse Community

The Treehouse Community is a meeting place for developers, designers, and programmers of all backgrounds and skill levels to get support. Collaborate here on code errors or bugs that you need feedback on, or asking for an extra set of eyes on your latest project. Join thousands of Treehouse students and alumni in the community today. (Note: Only Treehouse students can comment or ask questions, but non-students are welcome to browse our conversations.)

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and a supportive community. Start your free trial today.

JavaScript JavaScript Basics (Retired) Storing and Tracking Information with Variables Using String Methods

Abdullaziz Almajid
Abdullaziz Almajid
Courses Plus Student 2,686 Points

i don't understand this question can i get an answer with explanation?

Finally, add a # symbol and lastName in uppercase to the end of the userName string. The final value of userName is "23188XTR#SMITH"

var id = "23188xtr";
var lastName = "Smith";
var lastName ='#'
var userName =id.toUpperCase('#'+'lastName');
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
<script src="app.js"></script>

3 Answers

Christian Mangeng
Christian Mangeng
15,969 Points


the string that the challenge asks for is "23188XTR#SMITH". This string is composed of 3 parts:

1) the content of id in all uppercase letters

2) the # and

3) lastName in all uppercase letters

If you combine all three parts by string concatenation, you obtain the string that is asked for. Defining the variable userName as id.toUpperCase() is part of task 1 of the challenge. That's why we first define it like that, then add the rest of what is asked for to userName in a different step, so that userName finally stores "23188XTR#SMITH".

var id = "23188xtr";
var lastName = "Smith";

var userName = id.toUpperCase();
userName += '#' + lastName.toUpperCase();

Thank you for answering this question. I was going to ask the same question too.