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Python Python Basics (2015) Letter Game App Even or Odd Loop

Posted by Lakshmi R
Lakshmi R
2,568 Points

I don't understand what is wrong!

It gives a bummer! It looks like Task 1 is no longer passing!

What exactly is wrong with the code I have written?

even.py 
import random

start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    randnum = random.randint(1, 99)
    r = even_odd(randnum)
    if r == 1:
        print "{} is even".format(randnum)
    else:
        print "{} is odd".format(randnum)
    start -= 1

2 Answers

Keith Whatling
Keith Whatling
17,752 Points
Keith Whatling
Keith Whatling
17,752 Points

Hi,

Almost perfect, just need to add () around your print statements.

We have all done it, and will no doubt continue to do it!. I have found it a good idea to try the following.

Copy and past your code to python and test it. Take your coding hat off, and check it like you would another person's letter or email, looking for typos, grammar and spelling mistakes. sometimes walking away, having a coffee, coming back and physically read the code will help. It helps me anyway. (Did you notice I did not capitalise the S in sometimes, I didn't until I reread the text) :).

There is an old adage its easier to write new code to fix a problem that it is to read old code and amend/fix it. 

import random

start = 5
def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start > 0:
    randnum = random.randint(1, 99)
    r = even_odd(randnum)
    if r == 1:
        print ("{} is even".format(randnum))
    else:
        print ("{} is odd".format(randnum))
    start -= 1
Lakshmi R
Lakshmi R
2,568 Points

Thanks ! :)

Keith Whatling
Keith Whatling
17,752 Points
Keith Whatling
Keith Whatling
17,752 Points

No probs, i just did the challenge again, you can write it like this using 0 as falsey and anything else is true.

Note the use of start and the returned value from even_odd.

You're doing great keep going!

import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while start:
    ranNum = random.randint(1,99)
    if even_odd(ranNum):
        print ("{} is even".format(ranNum))
    else:
        print ("{} is odd".format(ranNum))
    start -= 1
Lakshmi R
Lakshmi R
2,568 Points

That's even better! Thanks again!