Welcome to the Treehouse Community
Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.
Looking to learn something new?
Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.
Start your free trialyoussef moustahib
2,303 PointsI dont understand what is wrong here? It works fine in workspaces
Great work! OK, you're doing great so I'll keep increasing the difficulty. For this step, make another new function named courses that will, again, take the dictionary of teachers and courses. courses, though, should return a single list of all of the available courses in the dictionary. No teachers, just course names!
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def courses(arg):
newlist = []
for value in arg.values():
for item in value:
newlist.append(item)
return newlist
def num_courses(arg):
total = 0
for value in arg.values():
for item in value:
total += 1
return total
def num_teachers(arg):
keys = 0
for key in arg.keys():
keys += 1
return keys
1 Answer
Chris Freeman
Treehouse Moderator 68,454 PointsYour so close. An indentation error was introduced in function num_courses
: the first for
loop is indented farther than the total
assignment statement above it.
Post back if you need more help. Good luck!!!
youssef moustahib
2,303 Pointsyoussef moustahib
2,303 PointsAnyone?