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Python Python Basics (2015) Letter Game App Even or Odd Loop

tangtai chen
tangtai chen
4,844 Points
Posted by tangtai chen
tangtai chen
4,844 Points

I don't understand what it asked for, i coded as much as i understood can someone help?

Here is my code, and here is some of the things i don't understand:

"Make a while loop that runs until start is falsey." start is defined as a number, where do i put it to falsey?

"putting the random number in the hole." does this means adding all the even numbers?

"Finally, decrement start by 1." so i can do start - 1, and turn start to falsely, i don't konw what it is asking for can someone help?

even.py 
import random
start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2

while True:
    num = random.randint(1,99)
    if even_odd(num) == False:
        print("{} is odd".format(num))
        start = start - 1
        break
    else:
        print("{} is even".format(num))

1 Answer

Christopher Shaw
seal-mask
PLUS
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points
Christopher Shaw
.a{fill-rule:evenodd;}techdegree seal-36
Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

You are on the right track, but have slightly misunderstood the question.

The while loop should always run 5 times, not break out when it receives an odd number. So remove break and move start = start - 1 to the end, outside the if else block.

You will also need to change the while statement to while start > 0

tangtai chen
tangtai chen
4,844 Points
tangtai chen
tangtai chen
4,844 Points

thx for the help, i got it right!