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Java Java Basics Getting Started with Java IO

David Geoffry
David Geoffry
444 Points

I don't understand why it is not reading that I have the "firstName" variable in the printf


// I have imported java.io.Console for you.  It is a variable calle

console.printf("First name:%s",firstName);

//First Name

String firstName = "Kelton";


  String FirstName = console.readLine ("What is your name?");


String lastName = "Rozell";


  String LastName = console.readLine ("What is your last name?");

2 Answers

james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

you have firstName, but then you also have FirstName. they are different. it wants you to use the camel cased one, but that one doesn't use console.readLine(), so that's one error. you also are referencing the firstName variable before it is declared. your use of the variable must come after it is declared for it to know what you are referencing. same thing with lastName and LastName going on too.