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JavaScript JavaScript Foundations Variables Shadowing

Posted by Matthew Lambdin
Matthew Lambdin
2,726 Points

I don't understand why Nick isn't the global variable.

I understand that using var person="Jim" outside of a function sets it for global scope. I also understand that not using the "var" inside of a function will declare it as a global variable. What I am missing is when person="Nick" is declared outside of a function does that not set it as a global variable? If not then, does not using var always trump non var. Thanks! --------- OK! The next video is on Hoisting and it explained my questions-------

J Scott Erickson
J Scott Erickson
11,883 Points
J Scott Erickson
J Scott Erickson
11,883 Points

code example?

NM! Saw your edit. Ha.

1 Answer

welcomeuniverse
welcomeuniverse
1,942 Points
welcomeuniverse
welcomeuniverse
1,942 Points

person="Nick" outside function will end up becoming global. If there is no var person then one is defined for you the compiler. Kinda crazy.. but I think it does. That is why it is a good idea to have all variables defined with var keywords and at top when it is global and top of function when it is gonna work inside your function only