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Python Python Collections (2016, retired 2019) Dictionaries Word Count

I don't understand why this isn't right. It works in pycharm with the example given.

I feel like I have the right answer. What am I missing?

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(string):
    myDict = {}
    for word in myString:
        if word in myDict:
            myDict[word] += 1
            myDict[word] = 1

word_count("I do not like it Sam I Am")

2 Answers

You are using print instead of return. For the task the function needs to return a dictionary

Also, you are lowercasing the dictionary. Are you sure the interpreter is expecting lowercase responses? Consider the following code:

def word_count(sentence):
   dictionary = {}
   for word in sentence.split():
      dictionary.update({word: sentence.count(word)})
   return dictionary

The code above will return the following when you enter word_count(sentence) into the interpreter:

{'I': 2, 'do': 1, 'not': 1, 'like': 1, 'it': 1, 'Sam': 1, 'Am': 1}