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iOS Swift Functions and Optionals Optionals Optional Chaining

Posted by Morten Engervik
Morten Engervik
1,420 Points

I get this error in the example with optionals/optionals chaining:

https://www.dropbox.com/s/e7h2sxjt63lczhd/Screenshot%202014-12-01%2008.06.59.png?dl=0

I guess the compiler is complaining about the String format in the array is not equal to the String format in the function parameter?

PS: Im a noob. Handle with care :)

2 Answers

Stephen Whitfield
Stephen Whitfield
16,771 Points
Stephen Whitfield
Stephen Whitfield
16,771 Points

The compiler is telling you that the array "aptNumbers" is not a String, it's an array, and can't be converted into a String. What's the problem here? You're comparing a String to an Array in your for-in loop. You should trying comparing "tempAptNumbers," which is a String object in the array "aptNumbers" to another String. Replace "aptNumbers" in your for-in loop to something like "404" and see what you get.

İLKAY KUSCU
İLKAY KUSCU
2,417 Points
İLKAY KUSCU
İLKAY KUSCU
2,417 Points

if (tempAptNumber == aptNumber) { return aptNumber }