## Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community!

### Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial###### ryota kurazono

Courses Plus Student 4,248 Points# I got stuck.

I don't know what to do. The error massage is "You need to pass the $numbers variable as an argument to array_sum()." I hope anyone help me.

```
<?php
$numbers = array(1,5,8);
/*
$sum = 0;
foreach($numbers as $number) {
$sum = $sum + $number;
}
echo $sum;
*/
function array_sum(){
$sum = 0;
$sum = $numbers[0] + $numbers[1] + $numbers[2] ;
return $sum;
}
array_sum();
?>
```

## 2 Answers

###### Algirdas Lalys

9,389 PointsHi ryota kurazono,
The code below creates an array of numbers, loops through them one at a time, and sums their values. PHP actually has a **native** function that does this same thing: array_sum(). Some of PHP functions are internal like **var_dump()**, **array_sum()**, and there is plenty more. Array functions in PHP. So you just need to replace your foreach loop with this internal function.

```
$sum = array_sum($numbers);
```

###### Aananya Vyas

20,157 Pointsthis worked for me:

$numbers = array(1,5,8); $sum = 0; $sum = array_sum($numbers); echo $sum;

## Ashish Mehra

3,407 Points## Ashish Mehra

3,407 PointsSteps