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Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.  # I have a different solution, is this correct?

```var minNumber = prompt("give your min number!");
var maxNumber = prompt("give your max number");

var diceRoll = Math.floor(Math.random() * parseInt(maxNumber) + parseInt(minNumber))+1;
```

I will have correct results, as far as I did test.... yep, looks like your code is correct.

Sorry. Changing my opinion, why? Because if you enter your max number 20 an min number 15, then if random generates 18, you add the min number and the answer is 33. Sorry for the wrong answer.

I found a bug. I set `minNumber` to 5, and `maxNumber` to 11, and I got 15.

Hint on fixing bug: Sometimes, `Math.random() * maxNumber` can be close to `maxNumber`, because `Math.random()` can be close to 1, and if you add `minNumber` to that quantity, it may be above `maxNumber`. The math being applied here is not correct for creating a random number that will be within the two limits entered. The formula shown here will give you a number with a minimum one higher than the lower value, and a maximum of the sum of the two numbers entered.

The correct formula for a within-range random number with even distribution is:

## `random * range + minimum`

where "range" is `maximum - minimum + 1`