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Java Java Basics Getting Started with Java Strings, Variables, and Formatting

Posted by Chance Goodman
Chance Goodman
448 Points

I have confusion with this question.

I would like to just be given an example.

Name.java 
String FirstName="Chance";
console.printf("%S is very confused rn")
Mathew Tran
Mathew Tran
Courses Plus Student 10,205 Points
Mathew Tran
Mathew Tran
Courses Plus Student 10,205 Points

The validator for some of these quizzes are pretty strict.

  • Note the first challenge where it says the variable needs to be "firstName". Note the camel casing.
  • For the second part of the challenge you almost have it, after using %s to in your printf call, you need to map it to a string variable.
console.printf("%s can code",firstName);

Matt.

1 Answer

Steven Mattia
Steven Mattia
1,698 Points
Steven Mattia
Steven Mattia
1,698 Points

You have it all right but just are not printing out the variable correctly. You do %s as a placeholder for a String that is coming up. In your case you use %s but do not provide the variable that should take that place so it does not know what to replace %s with. How you do this is add a comma after the text and add the variable like this:

String firstName = "Chance";
console.printf("%s is very confused rn", firstName);
Chance Goodman
Chance Goodman
448 Points

Thank you