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iOS Swift Collections and Control Flow Control Flow With Conditional Statements FizzBuzz Challenge

Taylor Thurston
Taylor Thurston
2,909 Points
Posted by Taylor Thurston
Taylor Thurston
2,909 Points

I have exactly what's written in the video (except I have tried it using both i and n. It tells me my logic is wrong.wtf

for i in 1...100 { if (i % 3 == 0) && (i % 5 == 0) { print("FizzBuzz") } else if (i % 3 == 0) { print("Fizz") } else if (i % 5 == 0) { print ("Buzz") } else { print(i) } }

That's my function. Runs in xcode just fine...

fizzBuzz.swift 
func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
  for n in 1...100 {
    if (n % 3 == 0) && (n % 5 == 0) {
        print("FizzBuzz")
    } else if (n % 3 == 0) {
        print("Fizz")
    } else if (n % 5 == 0) {
        print ("Buzz")
    } else {
        print(n)
    }
}
  // End code
  return "\(n)"
}

1 Answer

Brandon Mahoney
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
Brandon Mahoney
iOS Development with Swift Techdegree Graduate 30,149 Points
Brandon Mahoney
.a{fill-rule:evenodd;}techdegree seal-36
Brandon Mahoney
iOS Development with Swift Techdegree Graduate 30,149 Points

You have 3 issues with your code.

  1. You are checking the Int 'n' and not a range of 1-100. Remember 'n' is a undetermined Int which will be passed in when the function is called. If you were running through a range of numbers every time when the function is called there would be no point to having the n parameter.
  2. You must return and not print
  3. The default is already taken care of for you so you can delete your last 'else'.

In cases like this especially when you start working on your own projects the best thing to do is go back slowly over what you are trying to do and check each detail. I find that actually talking through what you're doing out loud can also help, basically just explain what you are doing and why.

func fizzBuzz(n: Int) -> String {
  // Enter your code between the two comment markers
     if (n % 3 == 0) && (n % 5 == 0) {
        return("FizzBuzz")
    } else if (n % 3 == 0) {
        return("Fizz")
    } else if (n % 5 == 0) {
        return ("Buzz")
    }
  // End code
  return "\(n)"
}