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I have been trying to solve this but my way doesn't work

time_machine.py
```import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

# Remember, you can't set "years" on a timedelta!
# Consider a year to be 365 days.

## Example
# time_machine(5, "minutes") => datetime(2015, 10, 21, 16, 34)

def time_machine(**kwargs):
td = datetime.timedelta(**kwargs)
if 'years' in kwargs:
tdd = datetime.timedelta(days = 365)
return starter + (td + (tdd * getattr(other, 'years')
return starter + td
```

def time_machine(time_int, years): if years == 'years': time_int = 365 years = 'days' return starter + datetime.timedelta(*{years : time_int})

The function should take a normal argument, you won't need "kwargs".
Another hint: you should also not need "getattr".

A simple solution for this problem is to first check if the string is 'years' and if so change the string to 'days' since timedelta will not except years as an argument. Then multiply the integer by 365 to get the equivalent number of days for the given number of years. Finally, return the duration as the difference of the starter datetime and the timedelta of the string and integer passed to the method as a literal dictionary with the ** prefix operator to unpack the dictionary.

```import datetime

starter = datetime.datetime(2015, 10, 21, 16, 29)

def time_machine(integer, string):
if string == 'years':
string = 'days'
integer *= 365
return starter + datetime.timedelta(**{string: integer})
```