I having trouble getting my code to work. Any thoughts would be greatly appreciated. Thanks!

Question

//The below explains what I want the program to do...
//If the priority is high, and money is there, item can be bought
//If there are no more high priority items and money is available, then medium priority items can be bought
//If there are no more medium priority items and money is available, then low priority items can be bought

var amountToSpend = 8000;

var data = [("bed", 2000, "high"), ("faucet", 200, "low"), ("table", 2000, "medium"),("chair", 800, "high")];

//The for loops order the priority from high to low but fail to pull in all the data and spit it out to the input function. Any ideas on how to do this?
for(var i = 0; i< data.length; i++) {
    if(data[i] === "high") {
        console.log(data[i]);
    }
}

for(var i = 0; i< data.length; i++) {
    if(data[i] === "medium") {
        console.log(data[i]);
    }
}

for(var i = 0; i< data.length; i++) {
    if(data[i] === "low") {
        console.log(data[i]);
    }
}

function input(item, amount, priority) {
    if(amountToSpend >=0 && amount <= amountToSpend) {
        if (priority === "high") {
            amountToSpend -= amount;
            console.log(item);
        }    
        else if (priority === "medium") {
            amountToSpend -= amount;
            console.log(item);

        }
        else if (priority === "low") {
            amountToSpend -= amount;
            console.log(item);
        }
        else {
            console.log("error");
        }   
    }
    return "Amount Left $" + amountToSpend;
}

Answer 1 · 2015-09-25T04:40:53Z

September 25, 2015 4:40am

Hi Rachel,

What you're looking to do is best done with a sorting algorithm. One of the most efficient sorting algorithms is the MergeSort algorithm — another one is the Quick Sort algorithm. I used MergeSort here. This way it'll run faster and your code will be more succinct. Anyway, here's one way to do what you're trying to do:

var items = [
    {
        name        :   "bed",
        cost        :   2000,
        priority    :   1 //"high"
    },
    {
        name        :   "faucet",
        cost        :   200,
        priority    :   3 //"low"
    },
    {
        name        :   "table",
        cost        :   2000,
        priority    :   2 //"medium"
    },
    {
        name        :   "chair",
        cost        :   800,
        priority    :   3 //"high"
    }
];

function merge(left, right) {
  var result = [],
      lLen = left.length,
      rLen = right.length,
      l = 0,
      r = 0;
  while(l < lLen && r < rLen){
     if(left[l].priority < right[r].priority) {
       result.push(left[l++]);
     }
     else {
       result.push(right[r++]);
    }
  }  
  //remaining part needs to be addred to the result
  return result.concat(left.slice(l)).concat(right.slice(r));
}
function mergeSort(arr) {
   var len = arr.length;
   if(len <2)
      return arr;
   var mid = Math.floor(len/2),
       left = arr.slice(0,mid),
       right =arr.slice(mid);
   //send left and right to the mergeSort to broke it down into pieces
   //then merge those
   return merge(mergeSort(left),mergeSort(right));
}

var whatShouldIBuy = function(possiblePurchases, cashInPocket) {
    var theVerdict = "You should buy ", i;
    var rankedPurchases = mergeSort(possiblePurchases).reverse();
    var cashLeft = cashInPocket;
    var shoppingList = [];

    for(i=0; i<rankedPurchases.length; i++) {

       if(rankedPurchases[i].cost <= cashLeft && cashLeft > 0) {

            cashLeft -= rankedPurchases[i].cost;
            shoppingList.push("the " + rankedPurchases[i].name);

       }
    }

    if(shoppingList.length <= 0) {
        return "Dude, you're broke. Go make some money!";
    }

    return theVerdict + shoppingList.join(" and ") + ". That will leave you with $" + cashLeft + " to keep your pocket warm!";
};

//console.log(whatShouldIBuy(items, 100)); //returns 'Dude, you're broke. Go make some money!'
//console.log(whatShouldIBuy(items, 500)); //returns 'You should buy the faucet. That will leave you with $300 to keep your pocket warm!'
//console.log(whatShouldIBuy(items, 1000)); //returns 'You should buy the faucet and the chair. That will leave you with $0 to keep your pocket warm!'
//console.log(whatShouldIBuy(items, 1500)); //returns 'You should buy the faucet and the chair. That will leave you with $500 to keep your pocket warm!'
//console.log(whatShouldIBuy(items, 3000)); //returns 'You should buy the faucet and the chair and the table. That will leave you with $0 to keep your pocket warm!'
//console.log(whatShouldIBuy(items, 5000)); //returns 'You should buy the faucet and the chair and the table and the bed. That will leave you with $0 to keep your pocket warm!'

To see it in action, simply call the whatShouldIBuy() function and give it an array of objects (your list of possible purchases) as the first argument and an Integer (the amount of cash in your pocket) as the second argument. Then, look in your browser's javascript console :)

Answer 2 · 2015-09-25T04:29:48Z

September 25, 2015 4:29am

Hope this helps..

  var data1 = [
  {saleItem : 'bed', price: 2000, priority : 1},     // 1 is high, 2 is medium, 3 is low priority  
  {saleItem : 'faucet', price: 200, priority : 3}, 
  {saleItem : 'table', price: 2000, priority : 2},
  {saleItem : 'chair', price: 800, priority : 1},
];

var totalData = data1.length - 1;
var canPurchase = true;
var listOfPurchaseable = [];
var  customerPocket = prompt('How much is your budget?');
var rAmount = parseInt(customerPocket);
var output;

function print(message) {  // print message
  document.write(message);
}

// sort data by price descending  & save to byPrice variable
var byPrice = data1.slice(0);
byPrice.sort(function(a,b) {
   return b.price - a.price;
});

var lowestPricePossible = parseInt(byPrice[totalData].price);

// sort data by priority high to low & save to byPriority variable
var byPriority = data1.slice(0);
byPriority.sort(function(a,b) {
   return a.priority - b.priority;
});


function getPossiblePurchase(customerPocket) {
    if(parseInt(customerPocket) < parseInt(lowestPricePossible))  {
      canPurchase = false;
    }else {
       for ( j=0; j < byPriority.length; j+=1) {
         if(parseInt(customerPocket) >=  parseFloat(byPriority[j].price)) {
          listOfPurchaseable.push([byPriority[j].saleItem, byPriority[j].price, byPriority[j].priority]); 
          customerPocket -= parseFloat(byPriority[j].price);
          byPriority.splice(j,1);
          return customerPocket;
         }
       } // for ends
    }  //else ends
    canPurchase = false;
    return customerPocket;
} // getPossiblePurchase ends

// MAIN LOOP
while (canPurchase) {   // loop while customerPocket is greater than lowest possible purchase item
   if (rAmount >= lowestPricePossible) {
    console.log(customerPocket);
    rAmount = getPossiblePurchase(rAmount);
  } else {
    canPurchase = false;
  }
} 

// print list of possible purchase
output = ' Your budget is : ' + customerPocket + '<br>';
if (listOfPurchaseable.length > 0) {
  for ( x=0; x < listOfPurchaseable.length; x++ ){
    output += 'Item : ' + listOfPurchaseable[x][0] + '<br>';
    output += 'Price : ' + listOfPurchaseable[x][1] + '<br>';
     output += 'Priority : ' + listOfPurchaseable[x][2] + '<br><br>';
  }
  output += 'Remaining Amount : ' + rAmount;
} else {
  output += ' Sorry your budget is too low ';
}
print(output);

/**
sample result

Your budget is : 4590
Item : bed
Price : 2000
Priority : 1

Item : chair
Price : 800
Priority : 1

Item : faucet
Price : 200
Priority : 3

Remaining Amount : 1590 
**/

Answer 3 · 2015-09-25T04:48:44Z

September 25, 2015 4:48am

i will try this!

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Rachel Miller

Rachel Miller

I having trouble getting my code to work. Any thoughts would be greatly appreciated. Thanks!

3 Answers

miikis

miikis

vanessa

vanessa

vanessa

vanessa

miikis

miikis

Rachel Miller

Rachel Miller