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JavaScript JavaScript Foundations Arrays Methods: Part 2

I just don't get it

The challenge question is: Sort the saying2 array, on about line 19, so that the words are listed in length order. The shortest first. Use the 'length' property on the strings in the sort function.

var saying1 = ["The", "quick", "brown", "fox", "jumps", "over", "the", "lazy", "dog"];
var saying2 = ["The", "quick", "brown", "fox", "jumped", "over", "the", "lazy", "dog's", "back"];
saying1.reverse();
saying2;
jdh
jdh
12,334 Points

hey!

you need to use the sort property then pass an anonymous function with two variables which you will add the length property to. The a.length - b.length in the below is acting like a comparison. let me know if you need more clarification

saying2.sort(function(a,b){
 return a.length - b.length;
});

Hi jdh,

You should re-post this as an answer.

1 Answer

jdh
jdh
12,334 Points

hey!

you need to use the sort property then pass an anonymous function with two variables which you will add the length property to. The a.length - b.length in the below is acting like a comparison. let me know if you need more clarification

            saying2.sort(function(a,b){
 return a.length - b.length;
});
            ```

Hi,

I'm not the OP for the thread, but I would very much appreciate clarification on this. Thanks.