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JavaScript AJAX Basics (retiring) Programming AJAX Stage 2 Challenge Answer

Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points
Posted by Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points

I left out the </li> and code still works?

var xhs=new XMLHttpRequest(); xhs.onreadystatechange=function(){ if(xhs.readyState===4){ var roomResponse=JSON.parse(xhs.responseText); var roomHTML='<ul class="rooms">' for(var i=0;i<roomResponse.length;i+=1){ if(roomResponse[i].available===true){ roomHTML+='<li class="empty">'} else{ roomHTML+='<li class="full">'} roomHTML+=roomResponse[i].room; } roomHTML+="</ul>"; document.getElementById('roomList').innerHTML=roomHTML

}

}

xhs.open('GET','../data/rooms.json'); xhs.send();

1 Answer

Steven Parker
Steven Parker
231,269 Points
Steven Parker
Steven Parker
231,269 Points

Browsers generally ignore HTML errors, and this may work either for or against your intentions. In the case of a missing end tag for a list element, you often see what you intended anyway.

But it is a "best practice" to always use proper syntax even if you know the bad syntax will still work.