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JavaScript AJAX Basics (retiring) Programming AJAX Stage 2 Challenge Answer

Leo Marco Corpuz
Leo Marco Corpuz
18,975 Points

I left out the </li> and code still works?

var xhs=new XMLHttpRequest(); xhs.onreadystatechange=function(){ if(xhs.readyState===4){ var roomResponse=JSON.parse(xhs.responseText); var roomHTML='<ul class="rooms">' for(var i=0;i<roomResponse.length;i+=1){ if(roomResponse[i].available===true){ roomHTML+='<li class="empty">'} else{ roomHTML+='<li class="full">'} roomHTML+=roomResponse[i].room; } roomHTML+="</ul>"; document.getElementById('roomList').innerHTML=roomHTML



xhs.open('GET','../data/rooms.json'); xhs.send();

1 Answer

Steven Parker
Steven Parker
228,001 Points

Browsers generally ignore HTML errors, and this may work either for or against your intentions. In the case of a missing end tag for a list element, you often see what you intended anyway.

But it is a "best practice" to always use proper syntax even if you know the bad syntax will still work.