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JavaScript AJAX Basics (retiring) jQuery and AJAX The Office Status Project Revisited

Mateo Buitrago
Mateo Buitrago
5,629 Points
Posted by Mateo Buitrago
Mateo Buitrago
5,629 Points

I looped trough the response array with "for", what is wrong with my code?

$(document).ready(function () {
  var url = "../data/employees.json";

  $.getJSON(url,function(response){
    var statusHTML = "<ul class='bulleted'>";

    for(var i=0;i<response.length;i++){
      if(response[i].inoffice){
        statusHTML += "<li class='in'>";
      } else {
        statusHTML += "<li class='out'>";
      } 

      statusHTML += response[i].name + "</li>"
    } 
    statusHTML += "</ul>";
    $("#employeeList").html = statusHTML;
 }); 
});

EDIT:

Already found the mistake Instead of

$("#employeeList").html = statusHTML;

is

$("#employeeList").html(statusHTML);

Any more suggestions for my code?

1 Answer

sibal gesekki
sibal gesekki
3,484 Points
sibal gesekki
sibal gesekki
3,484 Points 
$.getJSON('../data/employees.json', function(response) {
  var $employeeList = $('#employeeList');
  var $ul = $('<ul class="bulleted"></ul>');

  $.each(response, function(idx, obj) {
    var $li = $('<li></li>');
    if (obj.inoffice) {
      $li.addClass('in');
    } else {
      $li.addClass('out'); 
    }
      $li.html(obj.name);
      $ul.append($li);
  })
  $employeeList.append($ul);
});