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Python Functional Python Functional Workhorses Filter

i m getting Bummer: Try again on this task where am i going wrong?

Now create a variable named dt_2012 that uses filter() and is_2012 to return only the datetimes from dates that are from the year 2012.

filters.py
import datetime

dates = [
    datetime.datetime(2012, 12, 15),
    datetime.datetime(1987, 8, 20),
    datetime.datetime(1965, 2, 28),
    datetime.datetime(2015, 4, 29),
    datetime.datetime(2012, 6, 30),
]

def is_2012(argument):
    if argument.year == 2012:
         return True
        break
dt_2012 = filter(is_2012, dates)

4 Answers

Steven Parker
Steven Parker
210,850 Points

You really close, but a "break" is only used with a loop, and there's no loop here. Plus the indentation doesn't line up.

Just remove that line entirely and you'll pass the challenge.

i did what you advised @Steven Parker but i still get the error

just tried it and it worked i don't know what was wrong at first

gustavoalvarado
gustavoalvarado
4,111 Points

Thabang Richard Katlholo I looked at Steven Parker's advice (thanks by the way) and i fixed my code this way

import datetime

dates = [
    datetime.datetime(2012, 12, 15),
    datetime.datetime(1987, 8, 20),
    datetime.datetime(1965, 2, 28),
    datetime.datetime(2015, 4, 29),
    datetime.datetime(2012, 6, 30),
]
# Part 1
def is_2012(argument):
    if argument.year == 2012:
# The last mistake that made me lose patience and look for help, i typed
# datetime.datetime.year instead of argument.year
        return True
    else:
        return False

And thanks to you Thabang Richard Katlholo, your code also helped mine.